Skip to content

chore(CategoryTheory/Presentable): remove a backward.isDefEq set_option #42984

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Open
dennj wants to merge 6 commits into
base: master
Choose a base branch
from
Open

chore(CategoryTheory/Presentable): remove a backward.isDefEq set_option #42984

Changes from 3 commits
Commits
Show all changes
6 commits
Select commit Hold shift + click to select a range
ba4ca91
chore(CategoryTheory/Presentable): remove a backward.isDefEq set_option
dennj Aug 20, 2026
8bb7f03
use aesop with Subtype.ext_iff instead of explicit proof
dennj Aug 20, 2026
653422b
fix membership proof instead of aesop hint
dennj Aug 20, 2026
eecb605
Update Mathlib/CategoryTheory/Presentable/IsCardinalFiltered.lean
dennj Aug 21, 2026
730bf7f
inline rangeFactorization_surjective at use site
dennj Aug 21, 2026
b67a299
Merge branch 'master' into presentable-remove-isdefeq-setoption
dennj Aug 21, 2026
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
4 changes: 2 additions & 2 deletions Mathlib/CategoryTheory/Presentable/IsCardinalFiltered.lean
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -197,11 +197,11 @@ lemma isCardinalFiltered_preorder (J : Type w) [Preorder J]
{ app a := homOfLE (hj a)
naturality _ _ _ := rfl }⟩

set_option backward.isDefEq.respectTransparency.types false in
instance (κ : Cardinal.{w}) [hκ : Fact κ.IsRegular] :
IsCardinalFiltered κ.ord.ToType κ :=
isCardinalFiltered_preorder _ _ (fun ι f hs ↦ by
have h : Function.Surjective (fun i ↦ (⟨f i, i, rfl⟩ : Set.range f)) := fun _ ↦ by aesop
have h : Function.Surjective (fun i ↦ (⟨f i, Set.mem_range_self i⟩ : Set.range f)) :=
fun _ ↦ by aesop
Comment thread
dennj marked this conversation as resolved.
Outdated
contrapose! hs
rw [← hκ.out.cof_ord, ← Ordinal.cof_toType]
refine (Order.cof_le fun j ↦ ?_).trans (Cardinal.mk_le_of_surjective h)
Expand Down
Loading